1/(2x+1)=1(x+2)

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Solution for 1/(2x+1)=1(x+2) equation: 



1/(2x+1)=1(x+2)

We move all terms to the left:

1/(2x+1)-(1(x+2))=0



Domain of the equation: (2x+1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-1

x!=-1/2

x!=-1/2

x∈R



We multiply all the terms by the denominator


-((1(x+2)))*(2x+1)+1=0



We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parentheses: -((1(x+2)))*(2x+1), so:

(1(x+2)))*(2x+1





We calculate terms in parenthes

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