Y=2x(2)+12x+22

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Solution for Y=2x(2)+12x+22 equation: 



=2Y(2)+12Y+22

We move all terms to the left:

-(2Y(2)+12Y+22)=0

We add all the numbers together, and all the variables

-(+2Y^2+12Y+22)=0

We get rid of parentheses

-2Y^2-12Y-22=0

a = -2; b = -12; c = -22;
Δ = b2-4ac
Δ = -122-4·(-2)·(-22)
Δ = -32
Delta is less than zero, so there is no solution for the equation

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