10(d+3)-4(d-2)=7(d+5)

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Solution for 10(d+3)-4(d-2)=7(d+5) equation: 



10(d+3)-4(d-2)=7(d+5)

We move all terms to the left:

10(d+3)-4(d-2)-(7(d+5))=0

We multiply parentheses

10d-4d-(7(d+5))+30+8=0



We calculate terms in parentheses: -(7(d+5)), so:

7(d+5)

We multiply parentheses

7d+35

Back to the equation:

-(7d+35)



We add all the numbers together, and all the variables

6d-(7d+35)+38=0

We get rid of parentheses

6d-7d-35+38=0

We add all the numbers together, and all the variables

-1d+3=0

We move all terms containing d to the left, all other terms to the right

-d=-3

d=-3/-1

d=+3

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