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2/3-2/2-2/5y=3
We move all terms to the left:
2/3-2/2-2/5y-(3)=0
Domain of the equation: 5y!=0determiningTheFunctionDomain -2/5y-3+2/3-2/2=0
y!=0/5
y!=0
y∈R
We add all the numbers together, and all the variables
-2/5y-4+2/3=0
We calculate fractions
There is no solution for this equation
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