3(7-2a)=2(5-4a)

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Solution for 3(7-2a)=2(5-4a) equation: 



3(7-2a)=2(5-4a)

We move all terms to the left:

3(7-2a)-(2(5-4a))=0

We add all the numbers together, and all the variables

3(-2a+7)-(2(-4a+5))=0

We multiply parentheses

-6a-(2(-4a+5))+21=0



We calculate terms in parentheses: -(2(-4a+5)), so:

2(-4a+5)

We multiply parentheses

-8a+10

Back to the equation:

-(-8a+10)



We get rid of parentheses

-6a+8a-10+21=0

We add all the numbers together, and all the variables

2a+11=0

We move all terms containing a to the left, all other terms to the right

2a=-11

a=-11/2

a=-5+1/2

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