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=(5/3)Y-2
We move all terms to the left:
-((5/3)Y-2)=0
Domain of the equation: 3)Y-2)!=0We add all the numbers together, and all the variables
Y!=0/1
Y!=0
Y∈R
-((+5/3)Y-2)=0
We multiply all the terms by the denominator
-((+5=0
We add all the numbers together, and all the variables
=0
Y=0/1
Y=0
Równanie nie ma rozwiązania
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