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144=x2+10x
We move all terms to the left:
144-(x2+10x)=0
We add all the numbers together, and all the variables
-(+x^2+10x)+144=0
We get rid of parentheses
-x^2-10x+144=0
We add all the numbers together, and all the variables
-1x^2-10x+144=0
a = -1; b = -10; c = +144;
Δ = b2-4ac
Δ = -102-4·(-1)·144
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*-1}=\frac{-16}{-2} =+8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*-1}=\frac{36}{-2} =-18 $
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