X=-8/4x+10=

Solution for X=-8/4x+10= equation:

X=-8/4X+10=

We move all terms to the left:

X-(-8/4X+10)=0


Domain of the equation: 4X+10)!=0

X∈R


We get rid of parentheses

X+8/4X-10=0

We multiply all the terms by the denominator


X*4X-10*4X+8=0

Wy multiply elements

4X^2-40X+8=0

a = 4; b = -40; c = +8;
Δ = b2-4ac
Δ = -402-4·4·8
Δ = 1472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1472}=\sqrt{64*23}=\sqrt{64}*\sqrt{23}=8\sqrt{23}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-8\sqrt{23}}{2*4}=\frac{40-8\sqrt{23}}{8}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+8\sqrt{23}}{2*4}=\frac{40+8\sqrt{23}}{8}
$