x-9=8(2x+3)-28

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Solution for x-9=8(2x+3)-28 equation: 



x-9=8(2x+3)-28

We move all terms to the left:

x-9-(8(2x+3)-28)=0



We calculate terms in parentheses: -(8(2x+3)-28), so:

8(2x+3)-28

We multiply parentheses

16x+24-28

We add all the numbers together, and all the variables

16x-4

Back to the equation:

-(16x-4)



We get rid of parentheses

x-16x+4-9=0

We add all the numbers together, and all the variables

-15x-5=0

We move all terms containing x to the left, all other terms to the right

-15x=5

x=5/-15

x=-1/3

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