-(4y+3)/5=(1-2y)/2

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Solution for -(4y+3)/5=(1-2y)/2 equation: 



-(4y+3)/5=(1-2y)/2

We move all terms to the left:

-(4y+3)/5-((1-2y)/2)=0

We add all the numbers together, and all the variables

-(4y+3)/5-((-2y+1)/2)=0

We calculate fractions


(-4y)/()+(-((-2y+1)*5)/()=0



We calculate terms in parentheses: +(-((-2y+1)*5)/(), so:

-((-2y+1)*5)/(

We multiply all the terms by the denominator


-((-2y+1)*5)



We calculate terms in parentheses: -((-2y+1)*5), so:

(-2y+1)*5

We multiply parentheses

-10y+5

Back to the equation:

-(-10y+5)



We get rid of parentheses

10y-5

Back to the equation:

+(10y-5)



We get rid of parentheses

(-4y)/()+10y-5=0

We multiply all the terms by the denominator


(-4y)+10y*()-5*()=0

We add all the numbers together, and all the variables

(-4y)+10y*()=0

We get rid of parentheses

-4y+10y*()=0

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