X2=16+((-16+4x)+x(-4+x))

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Solution for X2=16+((-16+4x)+x(-4+x)) equation: 



X2=16+((-16+4X)+X(-4+X))

We move all terms to the left:

X2-(16+((-16+4X)+X(-4+X)))=0

We add all the numbers together, and all the variables

X2-(16+((4X-16)+X(X-4)))=0

We add all the numbers together, and all the variables

X^2-(16+((4X-16)+X(X-4)))=0



We calculate terms in parentheses: -(16+((4X-16)+X(X-4))), so:

16+((4X-16)+X(X-4))

determiningTheFunctionDomain
((4X-16)+X(X-4))+16



We calculate terms in parentheses: +((4X-16)+X(X-4)), so:

(4X-16)+X(X-4)

We multiply parentheses

X^2+(4X-16)-4X

We get rid of parentheses

X^2+4X-4X-16

We add all the numbers together, and all the variables

X^2-16

Back to the equation:

+(X^2-16)



We get rid of parentheses

X^2-16+16

We add all the numbers together, and all the variables

X^2

Back to the equation:

-(X^2)



We add all the numbers together, and all the variables

=0

X=0/1

X=0

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