5y+3=(-6)+4(1+3y)

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Solution for 5y+3=(-6)+4(1+3y) equation: 



5y+3=(-6)+4(1+3y)

We move all terms to the left:

5y+3-((-6)+4(1+3y))=0

We add all the numbers together, and all the variables

5y-((-6)+4(3y+1))+3=0



We calculate terms in parentheses: -((-6)+4(3y+1)), so:

(-6)+4(3y+1)

determiningTheFunctionDomain
4(3y+1)+(-6)

We add all the numbers together, and all the variables

4(3y+1)-6

We multiply parentheses

12y+4-6

We add all the numbers together, and all the variables

12y-2

Back to the equation:

-(12y-2)



We get rid of parentheses

5y-12y+2+3=0

We add all the numbers together, and all the variables

-7y+5=0

We move all terms containing y to the left, all other terms to the right

-7y=-5

y=-5/-7

y=5/7

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