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5y+3=(-6y)+4+12y
We move all terms to the left:
5y+3-((-6y)+4+12y)=0
We calculate terms in parentheses: -((-6y)+4+12y), so:We get rid of parentheses
(-6y)+4+12y
determiningTheFunctionDomain (-6y)+12y+4
We add all the numbers together, and all the variables
12y+(-6y)+4
We get rid of parentheses
12y-6y+4
We add all the numbers together, and all the variables
6y+4
Back to the equation:
-(6y+4)
5y-6y-4+3=0
We add all the numbers together, and all the variables
-1y-1=0
We move all terms containing y to the left, all other terms to the right
-y=1
y=1/-1
y=-1
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