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X2-28X-2996=0
We add all the numbers together, and all the variables
X^2-28X-2996=0
a = 1; b = -28; c = -2996;
Δ = b2-4ac
Δ = -282-4·1·(-2996)
Δ = 12768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12768}=\sqrt{16*798}=\sqrt{16}*\sqrt{798}=4\sqrt{798}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{798}}{2*1}=\frac{28-4\sqrt{798}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{798}}{2*1}=\frac{28+4\sqrt{798}}{2} $
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