14(z+3)=(4z+2)

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Solution for 14(z+3)=(4z+2) equation: 



14(z+3)=(4z+2)

We move all terms to the left:

14(z+3)-((4z+2))=0

We multiply parentheses

14z-((4z+2))+42=0



We calculate terms in parentheses: -((4z+2)), so:

(4z+2)

We get rid of parentheses

4z+2

Back to the equation:

-(4z+2)



We get rid of parentheses

14z-4z-2+42=0

We add all the numbers together, and all the variables

10z+40=0

We move all terms containing z to the left, all other terms to the right

10z=-40

z=-40/10

z=-4

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