X2-13x+6,25=0

Solution for X2-13x+6,25=0 equation:

X2-13X+6.25=0

We add all the numbers together, and all the variables

X^2-13X+6.25=0

a = 1; b = -13; c = +6.25;
Δ = b2-4ac
Δ = -132-4·1·6.25
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-12}{2*1}=\frac{1}{2}
=1/2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+12}{2*1}=\frac{25}{2}
=12+1/2
$