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X2-0.5X+0.0312=0
We add all the numbers together, and all the variables
X^2-0.5X+0.0312=0
a = 1; b = -0.5; c = +0.0312;
Δ = b2-4ac
Δ = -0.52-4·1·0.0312
Δ = 0.1252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.5)-\sqrt{0.1252}}{2*1}=\frac{0.5-\sqrt{0.1252}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.5)+\sqrt{0.1252}}{2*1}=\frac{0.5+\sqrt{0.1252}}{2} $
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