(3x-4)(x-2)=-8

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Solution for (3x-4)(x-2)=-8 equation: 



(3x-4)(x-2)=-8

We move all terms to the left:

(3x-4)(x-2)-(-8)=0

We add all the numbers together, and all the variables

(3x-4)(x-2)+8=0

We multiply parentheses ..

(+3x^2-6x-4x+8)+8=0

We get rid of parentheses

3x^2-6x-4x+8+8=0

We add all the numbers together, and all the variables

3x^2-10x+16=0

a = 3; b = -10; c = +16;
Δ = b2-4ac
Δ = -102-4·3·16
Δ = -92
Delta is less than zero, so there is no solution for the equation

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