5(x-2)-10=-2(x+3)+19x

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Solution for 5(x-2)-10=-2(x+3)+19x equation: 



5(x-2)-10=-2(x+3)+19x

We move all terms to the left:

5(x-2)-10-(-2(x+3)+19x)=0

We multiply parentheses

5x-(-2(x+3)+19x)-10-10=0



We calculate terms in parentheses: -(-2(x+3)+19x), so:

-2(x+3)+19x

We add all the numbers together, and all the variables

19x-2(x+3)

We multiply parentheses

19x-2x-6

We add all the numbers together, and all the variables

17x-6

Back to the equation:

-(17x-6)



We add all the numbers together, and all the variables

5x-(17x-6)-20=0

We get rid of parentheses

5x-17x+6-20=0

We add all the numbers together, and all the variables

-12x-14=0

We move all terms containing x to the left, all other terms to the right

-12x=14

x=14/-12

x=-1+1/6

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