X2+x-0.01=0

Solution for X2+x-0.01=0 equation:

X2+X-0.01=0

We add all the numbers together, and all the variables

X^2+X-0.01=0

a = 1; b = 1; c = -0.01;
Δ = b2-4ac
Δ = 12-4·1·(-0.01)
Δ = 1.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.04}}{2*1}=\frac{-1-\sqrt{1.04}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.04}}{2*1}=\frac{-1+\sqrt{1.04}}{2}
$