6(z+2)=-6

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Solution for 6(z+2)=-6 equation: 



6(z+2)=-6

We move all terms to the left:

6(z+2)-(-6)=0

We add all the numbers together, and all the variables

6(z+2)+6=0

We multiply parentheses

6z+12+6=0

We add all the numbers together, and all the variables

6z+18=0

We move all terms containing z to the left, all other terms to the right

6z=-18

z=-18/6

z=-3

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