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-2=1/5(3Y-1
We move all terms to the left:
-2-(1/5(3Y-1)=0
Domain of the equation: 5(3Y-1)-2!=0We multiply all the terms by the denominator
We move all terms containing Y to the left, all other terms to the right
5(3Y-1)!=2
Y∈R
-(1=0
We add all the numbers together, and all the variables
=0
Y=0/1
Y=0
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