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X2+8X-120=0
We add all the numbers together, and all the variables
X^2+8X-120=0
a = 1; b = 8; c = -120;
Δ = b2-4ac
Δ = 82-4·1·(-120)
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{34}}{2*1}=\frac{-8-4\sqrt{34}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{34}}{2*1}=\frac{-8+4\sqrt{34}}{2} $
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