20(3x)=(2x-5)

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Solution for 20(3x)=(2x-5) equation: 



20(3x)=(2x-5)

We move all terms to the left:

20(3x)-((2x-5))=0



We calculate terms in parentheses: -((2x-5)), so:

(2x-5)

We get rid of parentheses

2x-5

Back to the equation:

-(2x-5)



We get rid of parentheses

203x-2x+5=0

We add all the numbers together, and all the variables

201x+5=0

We move all terms containing x to the left, all other terms to the right

201x=-5

x=-5/201

x=-5/201

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