6(x-3)+3(x-3)=3(2x-16)-3(x-1)

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Solution for 6(x-3)+3(x-3)=3(2x-16)-3(x-1) equation: 



6(x-3)+3(x-3)=3(2x-16)-3(x-1)

We move all terms to the left:

6(x-3)+3(x-3)-(3(2x-16)-3(x-1))=0

We multiply parentheses

6x+3x-(3(2x-16)-3(x-1))-18-9=0



We calculate terms in parentheses: -(3(2x-16)-3(x-1)), so:

3(2x-16)-3(x-1)

We multiply parentheses

6x-3x-48+3

We add all the numbers together, and all the variables

3x-45

Back to the equation:

-(3x-45)



We add all the numbers together, and all the variables

9x-(3x-45)-27=0

We get rid of parentheses

9x-3x+45-27=0

We add all the numbers together, and all the variables

6x+18=0

We move all terms containing x to the left, all other terms to the right

6x=-18

x=-18/6

x=-3

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