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X2+250X-1=0
We add all the numbers together, and all the variables
X^2+250X-1=0
a = 1; b = 250; c = -1;
Δ = b2-4ac
Δ = 2502-4·1·(-1)
Δ = 62504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{62504}=\sqrt{4*15626}=\sqrt{4}*\sqrt{15626}=2\sqrt{15626}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-2\sqrt{15626}}{2*1}=\frac{-250-2\sqrt{15626}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+2\sqrt{15626}}{2*1}=\frac{-250+2\sqrt{15626}}{2} $
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