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x(36-x)=0
We add all the numbers together, and all the variables
x(-1x+36)=0
We multiply parentheses
-1x^2+36x=0
a = -1; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-1)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-1}=\frac{-72}{-2} =+36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-1}=\frac{0}{-2} =0 $
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