2(6a-4)=3(2a+10)

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Solution for 2(6a-4)=3(2a+10) equation: 



2(6a-4)=3(2a+10)

We move all terms to the left:

2(6a-4)-(3(2a+10))=0

We multiply parentheses

12a-(3(2a+10))-8=0



We calculate terms in parentheses: -(3(2a+10)), so:

3(2a+10)

We multiply parentheses

6a+30

Back to the equation:

-(6a+30)



We get rid of parentheses

12a-6a-30-8=0

We add all the numbers together, and all the variables

6a-38=0

We move all terms containing a to the left, all other terms to the right

6a=38

a=38/6

a=6+1/3

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