X2+20x+3=0

Solution for X2+20x+3=0 equation:

X2+20X+3=0

We add all the numbers together, and all the variables

X^2+20X+3=0

a = 1; b = 20; c = +3;
Δ = b2-4ac
Δ = 202-4·1·3
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-2\sqrt{97}}{2*1}=\frac{-20-2\sqrt{97}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+2\sqrt{97}}{2*1}=\frac{-20+2\sqrt{97}}{2}
$