(1+3x)(2+x)=-1+7x

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Solution for (1+3x)(2+x)=-1+7x equation: 



(1+3x)(2+x)=-1+7x

We move all terms to the left:

(1+3x)(2+x)-(-1+7x)=0

We add all the numbers together, and all the variables

(3x+1)(x+2)-(7x-1)=0

We get rid of parentheses

(3x+1)(x+2)-7x+1=0

We multiply parentheses ..

(+3x^2+6x+x+2)-7x+1=0

We get rid of parentheses

3x^2+6x+x-7x+2+1=0

We add all the numbers together, and all the variables

3x^2+3=0

a = 3; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·3·3
Δ = -36
Delta is less than zero, so there is no solution for the equation

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