H(x)=1-(2x+1)

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Solution for H(x)=1-(2x+1) equation: 



(H)=1-(2H+1)

We move all terms to the left:

(H)-(1-(2H+1))=0



We calculate terms in parentheses: -(1-(2H+1)), so:

1-(2H+1)

determiningTheFunctionDomain
-(2H+1)+1

We get rid of parentheses

-2H-1+1

We add all the numbers together, and all the variables

-2H

Back to the equation:

-(-2H)



We get rid of parentheses

H+2H=0

We add all the numbers together, and all the variables

3H=0

H=0/3

H=0

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