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X+5/6X=3X-7
We move all terms to the left:
X+5/6X-(3X-7)=0
Domain of the equation: 6X!=0We get rid of parentheses
X!=0/6
X!=0
X∈R
X+5/6X-3X+7=0
We multiply all the terms by the denominator
X*6X-3X*6X+7*6X+5=0
Wy multiply elements
6X^2-18X^2+42X+5=0
We add all the numbers together, and all the variables
-12X^2+42X+5=0
a = -12; b = 42; c = +5;
Δ = b2-4ac
Δ = 422-4·(-12)·5
Δ = 2004
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2004}=\sqrt{4*501}=\sqrt{4}*\sqrt{501}=2\sqrt{501}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-2\sqrt{501}}{2*-12}=\frac{-42-2\sqrt{501}}{-24} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+2\sqrt{501}}{2*-12}=\frac{-42+2\sqrt{501}}{-24} $
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