6(1+3a)+3(3+3a)=6a+6a

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Solution for 6(1+3a)+3(3+3a)=6a+6a equation: 



6(1+3a)+3(3+3a)=6a+6a

We move all terms to the left:

6(1+3a)+3(3+3a)-(6a+6a)=0

We add all the numbers together, and all the variables

6(3a+1)+3(3a+3)-(+12a)=0

We multiply parentheses

18a+9a-(+12a)+6+9=0

We get rid of parentheses

18a+9a-12a+6+9=0

We add all the numbers together, and all the variables

15a+15=0

We move all terms containing a to the left, all other terms to the right

15a=-15

a=-15/15

a=-1

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