X+(3/x)=(3-3x)/x

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Solution for X+(3/x)=(3-3x)/x equation: 



X+(3/X)=(3-3X)/X

We move all terms to the left:

X+(3/X)-((3-3X)/X)=0



Domain of the equation: X)!=0

X!=0/1

X!=0

X∈R



We add all the numbers together, and all the variables

X+(+3/X)-((-3X+3)/X)=0

We get rid of parentheses

X+3/X-((-3X+3)/X)=0

We calculate fractions


X+3X/X^2+(-((-3X+3)*X)/X^2=0

We multiply all the terms by the denominator


X*X^2+3X+(-((-3X+3)*X)=0



We calculate terms in parentheses: +(-((-3X+3)*X), so:

-((-3X+3)*X



We add all the numbers together, and all the variables

3X+X*X^2+(-((-3X+3)*X)=0

Wy multiply elements

X^3+3X+(-((-3X+3)*X)=0



We calculate terms in parentheses: +(-((-3X+3)*X), so:

-((-3X+3)*X



We do not support eXpression: X^3

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