(x-1)/2=(2x-8)/6

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Solution for (x-1)/2=(2x-8)/6 equation: 



(x-1)/2=(2x-8)/6

We move all terms to the left:

(x-1)/2-((2x-8)/6)=0

We calculate fractions


x/()+(-((2x-8)*2)/()=0



We calculate terms in parentheses: +(-((2x-8)*2)/(), so:

-((2x-8)*2)/(

We multiply all the terms by the denominator


-((2x-8)*2)



We calculate terms in parentheses: -((2x-8)*2), so:

(2x-8)*2

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We get rid of parentheses

-4x+16

Back to the equation:

+(-4x+16)



We get rid of parentheses

x/()-4x+16=0

We multiply all the terms by the denominator


x-4x*()+16*()=0

We add all the numbers together, and all the variables

x-4x*()=0

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