T(n)=3n2+n+16

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Solution for T(n)=3n2+n+16 equation: 



(T)=3T^2+T+16

We move all terms to the left:

(T)-(3T^2+T+16)=0

We get rid of parentheses

-3T^2+T-T-16=0

We add all the numbers together, and all the variables

-3T^2-16=0

a = -3; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·(-3)·(-16)
Δ = -192
Delta is less than zero, so there is no solution for the equation

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