(2/3x)-(1/2)(4x-1)=x+2(x-3)

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Solution for (2/3x)-(1/2)(4x-1)=x+2(x-3) equation: 



(2/3x)-(1/2)(4x-1)=x+2(x-3)

We move all terms to the left:

(2/3x)-(1/2)(4x-1)-(x+2(x-3))=0



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 2)(4x-1)!=0

x∈R



We add all the numbers together, and all the variables

(+2/3x)-(+1/2)(4x-1)-(x+2(x-3))=0

We get rid of parentheses

2/3x-(+1/2)(4x-1)-(x+2(x-3))=0

We multiply parentheses ..

-(+4x^2+1/2*-1)+2/3x-(x+2(x-3))=0

We calculate fractions


(-(+4x^2+1*3x)/(-1)*3x+2*)-(x+2(x-3))+()/(-1)*3x+2*)=0



We calculate terms in parentheses: +(-(+4x^2+1*3x)/(-1)*3x+2*), so:

-(+4x^2+1*3x)/(-1)*3x+2*

We add all the numbers together, and all the variables

-(+4x^2+1*3x)/(-1)*3x

We multiply all the terms by the denominator


-(+4x^2+1*3x)

We get rid of parentheses

-4x^2-1*3x

Wy multiply elements

-4x^2-3x

Back to the equation:

+(-4x^2-3x)





We calculate terms in parentheses: -(x+2(x-3)), so:

x+2(x-3)

We multiply parentheses

x+2x-6

We add all the numbers together, and all the variables

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

(-4x^2-3x)-(3x-6)+()/(-1)*3x=0

We get rid of parentheses

-4x^2-3x-3x+()/(-1)*3x+6=0

We multiply all the terms by the denominator


-4x^2*(-1)*3x-3x*(-1)*3x-3x*(-1)*3x+6*(-1)*3x+()=0

We add all the numbers together, and all the variables

-4x^2*(-1)*3x-3x*(-1)*3x-3x*(-1)*3x+6*(-1)*3x=0

We multiply parentheses

-4x^2*(-1)*3x+9x^2+9x^2-18x=0

We add all the numbers together, and all the variables

18x^2-4x^2*(-1)*3x-18x=0

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