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(3x+25)+(5x+12)=(2x+55)
We move all terms to the left:
(3x+25)+(5x+12)-((2x+55))=0
We get rid of parentheses
3x+5x-((2x+55))+25+12=0
We calculate terms in parentheses: -((2x+55)), so:We add all the numbers together, and all the variables
(2x+55)
We get rid of parentheses
2x+55
Back to the equation:
-(2x+55)
8x-(2x+55)+37=0
We get rid of parentheses
8x-2x-55+37=0
We add all the numbers together, and all the variables
6x-18=0
We move all terms containing x to the left, all other terms to the right
6x=18
x=18/6
x=3
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