S=(12x-40)+(3x-13)

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Solution for S=(12x-40)+(3x-13) equation: 



=(12S-40)+(3S-13)

We move all terms to the left:

-((12S-40)+(3S-13))=0



We calculate terms in parentheses: -((12S-40)+(3S-13)), so:

(12S-40)+(3S-13)

We get rid of parentheses

12S+3S-40-13

We add all the numbers together, and all the variables

15S-53

Back to the equation:

-(15S-53)



We get rid of parentheses

-15S+53=0

We move all terms containing S to the left, all other terms to the right

-15S=-53

S=-53/-15

S=3+8/15

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