5(z+1)+14=19-2z+4z

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Solution for 5(z+1)+14=19-2z+4z equation: 



5(z+1)+14=19-2z+4z

We move all terms to the left:

5(z+1)+14-(19-2z+4z)=0

We add all the numbers together, and all the variables

5(z+1)-(2z+19)+14=0

We multiply parentheses

5z-(2z+19)+5+14=0

We get rid of parentheses

5z-2z-19+5+14=0

We add all the numbers together, and all the variables

3z=0

z=0/3

z=0

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