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8c^2+30c-27=0
a = 8; b = 30; c = -27;
Δ = b2-4ac
Δ = 302-4·8·(-27)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-42}{2*8}=\frac{-72}{16} =-4+1/2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+42}{2*8}=\frac{12}{16} =3/4 $
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