(4-a)=3(a-4)

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Solution for (4-a)=3(a-4) equation: 



(4-a)=3(a-4)

We move all terms to the left:

(4-a)-(3(a-4))=0

We add all the numbers together, and all the variables

(-1a+4)-(3(a-4))=0

We get rid of parentheses

-1a-(3(a-4))+4=0



We calculate terms in parentheses: -(3(a-4)), so:

3(a-4)

We multiply parentheses

3a-12

Back to the equation:

-(3a-12)



We get rid of parentheses

-1a-3a+12+4=0

We add all the numbers together, and all the variables

-4a+16=0

We move all terms containing a to the left, all other terms to the right

-4a=-16

a=-16/-4

a=+4

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