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(R)=-10R^2+130R
We move all terms to the left:
(R)-(-10R^2+130R)=0
We get rid of parentheses
10R^2-130R+R=0
We add all the numbers together, and all the variables
10R^2-129R=0
a = 10; b = -129; c = 0;
Δ = b2-4ac
Δ = -1292-4·10·0
Δ = 16641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16641}=129$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-129)-129}{2*10}=\frac{0}{20} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-129)+129}{2*10}=\frac{258}{20} =12+9/10 $
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