11(c-2)+3=2+c-21

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Solution for 11(c-2)+3=2+c-21 equation: 



11(c-2)+3=2+c-21

We move all terms to the left:

11(c-2)+3-(2+c-21)=0

We add all the numbers together, and all the variables

11(c-2)-(c-19)+3=0

We multiply parentheses

11c-(c-19)-22+3=0

We get rid of parentheses

11c-c+19-22+3=0

We add all the numbers together, and all the variables

10c=0

c=0/10

c=0

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