5(u+1)-I=3(u-1)+7

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Solution for 5(u+1)-I=3(u-1)+7 equation: 



5(u+1)-=3(u-1)+7

We move all terms to the left:

5(u+1)--(3(u-1)+7)=0

We add all the numbers together, and all the variables

5(u+1)-(3(u-1)+7)=0

We multiply parentheses

5u-(3(u-1)+7)+5=0



We calculate terms in parentheses: -(3(u-1)+7), so:

3(u-1)+7

We multiply parentheses

3u-3+7

We add all the numbers together, and all the variables

3u+4

Back to the equation:

-(3u+4)



We get rid of parentheses

5u-3u-4+5=0

We add all the numbers together, and all the variables

2u+1=0

We move all terms containing u to the left, all other terms to the right

2u=-1

u=-1/2

u=-1/2

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