4(2v-5)-(v=2)

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Solution for 4(2v-5)-(v=2) equation: 



4(2v-5)-(v=2)

We move all terms to the left:

4(2v-5)-(v-(2))=0

We multiply parentheses

8v-(v-2)-20=0

We get rid of parentheses

8v-v+2-20=0

We add all the numbers together, and all the variables

7v-18=0

We move all terms containing v to the left, all other terms to the right

7v=18

v=18/7

v=2+4/7

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