Q4v+6=2(5+7v)-4

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Solution for Q4v+6=2(5+7v)-4 equation:



4Q+6=2(5+7Q)-4
We move all terms to the left:
4Q+6-(2(5+7Q)-4)=0
We add all the numbers together, and all the variables
4Q-(2(7Q+5)-4)+6=0
We calculate terms in parentheses: -(2(7Q+5)-4), so:
2(7Q+5)-4
We multiply parentheses
14Q+10-4
We add all the numbers together, and all the variables
14Q+6
Back to the equation:
-(14Q+6)
We get rid of parentheses
4Q-14Q-6+6=0
We add all the numbers together, and all the variables
-10Q=0
Q=0/-10
Q=0

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