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x+4/3x=150
We move all terms to the left:
x+4/3x-(150)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x*3x-150*3x+4=0
Wy multiply elements
3x^2-450x+4=0
a = 3; b = -450; c = +4;
Δ = b2-4ac
Δ = -4502-4·3·4
Δ = 202452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{202452}=\sqrt{4*50613}=\sqrt{4}*\sqrt{50613}=2\sqrt{50613}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-450)-2\sqrt{50613}}{2*3}=\frac{450-2\sqrt{50613}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-450)+2\sqrt{50613}}{2*3}=\frac{450+2\sqrt{50613}}{6} $
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