7(7c+1)-14c=13(3c-2)

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Solution for 7(7c+1)-14c=13(3c-2) equation: 



7(7c+1)-14c=13(3c-2)

We move all terms to the left:

7(7c+1)-14c-(13(3c-2))=0

We add all the numbers together, and all the variables

-14c+7(7c+1)-(13(3c-2))=0

We multiply parentheses

-14c+49c-(13(3c-2))+7=0



We calculate terms in parentheses: -(13(3c-2)), so:

13(3c-2)

We multiply parentheses

39c-26

Back to the equation:

-(39c-26)



We add all the numbers together, and all the variables

35c-(39c-26)+7=0

We get rid of parentheses

35c-39c+26+7=0

We add all the numbers together, and all the variables

-4c+33=0

We move all terms containing c to the left, all other terms to the right

-4c=-33

c=-33/-4

c=8+1/4

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