P(x)=-0.02x2+38x-5250.

Solution for P(x)=-0.02x2+38x-5250. equation:

(P)=-0.02P^2+38P-5250.

We move all terms to the left:

(P)-(-0.02P^2+38P-5250.)=0

We get rid of parentheses

0.02P^2-38P+P+5250.=0

We add all the numbers together, and all the variables

0.02P^2-37P+5250=0

a = 0.02; b = -37; c = +5250;
Δ = b2-4ac
Δ = -372-4·0.02·5250
Δ = 949
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{949}}{2*0.02}=\frac{37-\sqrt{949}}{0.04}
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{949}}{2*0.02}=\frac{37+\sqrt{949}}{0.04}
$